3.3.10 \(\int \cos ^3(c+d x) \sin (a+b x) \, dx\) [210]

Optimal. Leaf size=91 \[ -\frac {\cos (a-3 c+(b-3 d) x)}{8 (b-3 d)}-\frac {3 \cos (a-c+(b-d) x)}{8 (b-d)}-\frac {3 \cos (a+c+(b+d) x)}{8 (b+d)}-\frac {\cos (a+3 c+(b+3 d) x)}{8 (b+3 d)} \]

[Out]

-1/8*cos(a-3*c+(b-3*d)*x)/(b-3*d)-3/8*cos(a-c+(b-d)*x)/(b-d)-3/8*cos(a+c+(b+d)*x)/(b+d)-1/8*cos(a+3*c+(b+3*d)*
x)/(b+3*d)

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Rubi [A]
time = 0.05, antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {4670, 2718} \begin {gather*} -\frac {\cos (a+x (b-3 d)-3 c)}{8 (b-3 d)}-\frac {3 \cos (a+x (b-d)-c)}{8 (b-d)}-\frac {3 \cos (a+x (b+d)+c)}{8 (b+d)}-\frac {\cos (a+x (b+3 d)+3 c)}{8 (b+3 d)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^3*Sin[a + b*x],x]

[Out]

-1/8*Cos[a - 3*c + (b - 3*d)*x]/(b - 3*d) - (3*Cos[a - c + (b - d)*x])/(8*(b - d)) - (3*Cos[a + c + (b + d)*x]
)/(8*(b + d)) - Cos[a + 3*c + (b + 3*d)*x]/(8*(b + 3*d))

Rule 2718

Int[sin[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Cos[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rule 4670

Int[Cos[w_]^(q_.)*Sin[v_]^(p_.), x_Symbol] :> Int[ExpandTrigReduce[Sin[v]^p*Cos[w]^q, x], x] /; IGtQ[p, 0] &&
IGtQ[q, 0] && ((PolynomialQ[v, x] && PolynomialQ[w, x]) || (BinomialQ[{v, w}, x] && IndependentQ[Cancel[v/w],
x]))

Rubi steps

\begin {align*} \int \cos ^3(c+d x) \sin (a+b x) \, dx &=\int \left (\frac {1}{8} \sin (a-3 c+(b-3 d) x)+\frac {3}{8} \sin (a-c+(b-d) x)+\frac {3}{8} \sin (a+c+(b+d) x)+\frac {1}{8} \sin (a+3 c+(b+3 d) x)\right ) \, dx\\ &=\frac {1}{8} \int \sin (a-3 c+(b-3 d) x) \, dx+\frac {1}{8} \int \sin (a+3 c+(b+3 d) x) \, dx+\frac {3}{8} \int \sin (a-c+(b-d) x) \, dx+\frac {3}{8} \int \sin (a+c+(b+d) x) \, dx\\ &=-\frac {\cos (a-3 c+(b-3 d) x)}{8 (b-3 d)}-\frac {3 \cos (a-c+(b-d) x)}{8 (b-d)}-\frac {3 \cos (a+c+(b+d) x)}{8 (b+d)}-\frac {\cos (a+3 c+(b+3 d) x)}{8 (b+3 d)}\\ \end {align*}

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Mathematica [A]
time = 0.53, size = 87, normalized size = 0.96 \begin {gather*} \frac {1}{8} \left (-\frac {\cos (a-3 c+b x-3 d x)}{b-3 d}-\frac {3 \cos (a-c+b x-d x)}{b-d}-\frac {\cos (a+3 c+b x+3 d x)}{b+3 d}-\frac {3 \cos (a+c+(b+d) x)}{b+d}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^3*Sin[a + b*x],x]

[Out]

(-(Cos[a - 3*c + b*x - 3*d*x]/(b - 3*d)) - (3*Cos[a - c + b*x - d*x])/(b - d) - Cos[a + 3*c + b*x + 3*d*x]/(b
+ 3*d) - (3*Cos[a + c + (b + d)*x])/(b + d))/8

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Maple [A]
time = 0.18, size = 84, normalized size = 0.92

method	result	size
default	\(-\frac {\cos \left (a -3 c +\left (b -3 d \right ) x \right )}{8 \left (b -3 d \right )}-\frac {3 \cos \left (a -c +\left (b -d \right ) x \right )}{8 \left (b -d \right )}-\frac {3 \cos \left (a +c +\left (b +d \right ) x \right )}{8 \left (b +d \right )}-\frac {\cos \left (a +3 c +\left (b +3 d \right ) x \right )}{8 \left (b +3 d \right )}\)	\(84\)
risch	\(-\frac {\cos \left (b x -3 d x +a -3 c \right )}{8 \left (b -3 d \right )}-\frac {3 \cos \left (b x -d x +a -c \right )}{8 \left (b -d \right )}-\frac {3 \cos \left (b x +d x +a +c \right )}{8 \left (b +d \right )}-\frac {\cos \left (b x +3 d x +a +3 c \right )}{8 \left (b +3 d \right )}\)	\(85\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^3*sin(b*x+a),x,method=_RETURNVERBOSE)

[Out]

-1/8*cos(a-3*c+(b-3*d)*x)/(b-3*d)-3/8*cos(a-c+(b-d)*x)/(b-d)-3/8*cos(a+c+(b+d)*x)/(b+d)-1/8*cos(a+3*c+(b+3*d)*
x)/(b+3*d)

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 912 vs. \(2 (83) = 166\).
time = 0.32, size = 912, normalized size = 10.02 \begin {gather*} -\frac {{\left (b^{3} \cos \left (3 \, c\right ) - 3 \, b^{2} d \cos \left (3 \, c\right ) - b d^{2} \cos \left (3 \, c\right ) + 3 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left ({\left (b + 3 \, d\right )} x + a + 6 \, c\right ) + {\left (b^{3} \cos \left (3 \, c\right ) - 3 \, b^{2} d \cos \left (3 \, c\right ) - b d^{2} \cos \left (3 \, c\right ) + 3 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left ({\left (b + 3 \, d\right )} x + a\right ) + 3 \, {\left (b^{3} \cos \left (3 \, c\right ) - b^{2} d \cos \left (3 \, c\right ) - 9 \, b d^{2} \cos \left (3 \, c\right ) + 9 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left ({\left (b + d\right )} x + a + 4 \, c\right ) + 3 \, {\left (b^{3} \cos \left (3 \, c\right ) - b^{2} d \cos \left (3 \, c\right ) - 9 \, b d^{2} \cos \left (3 \, c\right ) + 9 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left ({\left (b + d\right )} x + a - 2 \, c\right ) + 3 \, {\left (b^{3} \cos \left (3 \, c\right ) + b^{2} d \cos \left (3 \, c\right ) - 9 \, b d^{2} \cos \left (3 \, c\right ) - 9 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left (-{\left (b - d\right )} x - a + 4 \, c\right ) + 3 \, {\left (b^{3} \cos \left (3 \, c\right ) + b^{2} d \cos \left (3 \, c\right ) - 9 \, b d^{2} \cos \left (3 \, c\right ) - 9 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left (-{\left (b - d\right )} x - a - 2 \, c\right ) + {\left (b^{3} \cos \left (3 \, c\right ) + 3 \, b^{2} d \cos \left (3 \, c\right ) - b d^{2} \cos \left (3 \, c\right ) - 3 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left (-{\left (b - 3 \, d\right )} x - a + 6 \, c\right ) + {\left (b^{3} \cos \left (3 \, c\right ) + 3 \, b^{2} d \cos \left (3 \, c\right ) - b d^{2} \cos \left (3 \, c\right ) - 3 \, d^{3} \cos \left (3 \, c\right )\right )} \cos \left (-{\left (b - 3 \, d\right )} x - a\right ) + {\left (b^{3} \sin \left (3 \, c\right ) - 3 \, b^{2} d \sin \left (3 \, c\right ) - b d^{2} \sin \left (3 \, c\right ) + 3 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left ({\left (b + 3 \, d\right )} x + a + 6 \, c\right ) - {\left (b^{3} \sin \left (3 \, c\right ) - 3 \, b^{2} d \sin \left (3 \, c\right ) - b d^{2} \sin \left (3 \, c\right ) + 3 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left ({\left (b + 3 \, d\right )} x + a\right ) + 3 \, {\left (b^{3} \sin \left (3 \, c\right ) - b^{2} d \sin \left (3 \, c\right ) - 9 \, b d^{2} \sin \left (3 \, c\right ) + 9 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left ({\left (b + d\right )} x + a + 4 \, c\right ) - 3 \, {\left (b^{3} \sin \left (3 \, c\right ) - b^{2} d \sin \left (3 \, c\right ) - 9 \, b d^{2} \sin \left (3 \, c\right ) + 9 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left ({\left (b + d\right )} x + a - 2 \, c\right ) + 3 \, {\left (b^{3} \sin \left (3 \, c\right ) + b^{2} d \sin \left (3 \, c\right ) - 9 \, b d^{2} \sin \left (3 \, c\right ) - 9 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left (-{\left (b - d\right )} x - a + 4 \, c\right ) - 3 \, {\left (b^{3} \sin \left (3 \, c\right ) + b^{2} d \sin \left (3 \, c\right ) - 9 \, b d^{2} \sin \left (3 \, c\right ) - 9 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left (-{\left (b - d\right )} x - a - 2 \, c\right ) + {\left (b^{3} \sin \left (3 \, c\right ) + 3 \, b^{2} d \sin \left (3 \, c\right ) - b d^{2} \sin \left (3 \, c\right ) - 3 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left (-{\left (b - 3 \, d\right )} x - a + 6 \, c\right ) - {\left (b^{3} \sin \left (3 \, c\right ) + 3 \, b^{2} d \sin \left (3 \, c\right ) - b d^{2} \sin \left (3 \, c\right ) - 3 \, d^{3} \sin \left (3 \, c\right )\right )} \sin \left (-{\left (b - 3 \, d\right )} x - a\right )}{16 \, {\left (b^{4} \cos \left (3 \, c\right )^{2} + b^{4} \sin \left (3 \, c\right )^{2} + 9 \, {\left (\cos \left (3 \, c\right )^{2} + \sin \left (3 \, c\right )^{2}\right )} d^{4} - 10 \, {\left (b^{2} \cos \left (3 \, c\right )^{2} + b^{2} \sin \left (3 \, c\right )^{2}\right )} d^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^3*sin(b*x+a),x, algorithm="maxima")

[Out]

-1/16*((b^3*cos(3*c) - 3*b^2*d*cos(3*c) - b*d^2*cos(3*c) + 3*d^3*cos(3*c))*cos((b + 3*d)*x + a + 6*c) + (b^3*c
os(3*c) - 3*b^2*d*cos(3*c) - b*d^2*cos(3*c) + 3*d^3*cos(3*c))*cos((b + 3*d)*x + a) + 3*(b^3*cos(3*c) - b^2*d*c
os(3*c) - 9*b*d^2*cos(3*c) + 9*d^3*cos(3*c))*cos((b + d)*x + a + 4*c) + 3*(b^3*cos(3*c) - b^2*d*cos(3*c) - 9*b
*d^2*cos(3*c) + 9*d^3*cos(3*c))*cos((b + d)*x + a - 2*c) + 3*(b^3*cos(3*c) + b^2*d*cos(3*c) - 9*b*d^2*cos(3*c)
- 9*d^3*cos(3*c))*cos(-(b - d)*x - a + 4*c) + 3*(b^3*cos(3*c) + b^2*d*cos(3*c) - 9*b*d^2*cos(3*c) - 9*d^3*cos
(3*c))*cos(-(b - d)*x - a - 2*c) + (b^3*cos(3*c) + 3*b^2*d*cos(3*c) - b*d^2*cos(3*c) - 3*d^3*cos(3*c))*cos(-(b
- 3*d)*x - a + 6*c) + (b^3*cos(3*c) + 3*b^2*d*cos(3*c) - b*d^2*cos(3*c) - 3*d^3*cos(3*c))*cos(-(b - 3*d)*x -
a) + (b^3*sin(3*c) - 3*b^2*d*sin(3*c) - b*d^2*sin(3*c) + 3*d^3*sin(3*c))*sin((b + 3*d)*x + a + 6*c) - (b^3*sin
(3*c) - 3*b^2*d*sin(3*c) - b*d^2*sin(3*c) + 3*d^3*sin(3*c))*sin((b + 3*d)*x + a) + 3*(b^3*sin(3*c) - b^2*d*sin
(3*c) - 9*b*d^2*sin(3*c) + 9*d^3*sin(3*c))*sin((b + d)*x + a + 4*c) - 3*(b^3*sin(3*c) - b^2*d*sin(3*c) - 9*b*d
^2*sin(3*c) + 9*d^3*sin(3*c))*sin((b + d)*x + a - 2*c) + 3*(b^3*sin(3*c) + b^2*d*sin(3*c) - 9*b*d^2*sin(3*c) -
9*d^3*sin(3*c))*sin(-(b - d)*x - a + 4*c) - 3*(b^3*sin(3*c) + b^2*d*sin(3*c) - 9*b*d^2*sin(3*c) - 9*d^3*sin(3
*c))*sin(-(b - d)*x - a - 2*c) + (b^3*sin(3*c) + 3*b^2*d*sin(3*c) - b*d^2*sin(3*c) - 3*d^3*sin(3*c))*sin(-(b -
3*d)*x - a + 6*c) - (b^3*sin(3*c) + 3*b^2*d*sin(3*c) - b*d^2*sin(3*c) - 3*d^3*sin(3*c))*sin(-(b - 3*d)*x - a)
)/(b^4*cos(3*c)^2 + b^4*sin(3*c)^2 + 9*(cos(3*c)^2 + sin(3*c)^2)*d^4 - 10*(b^2*cos(3*c)^2 + b^2*sin(3*c)^2)*d^
2)

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Fricas [A]
time = 2.10, size = 106, normalized size = 1.16 \begin {gather*} \frac {6 \, b d^{2} \cos \left (b x + a\right ) \cos \left (d x + c\right ) - {\left (b^{3} - b d^{2}\right )} \cos \left (b x + a\right ) \cos \left (d x + c\right )^{3} + 3 \, {\left (2 \, d^{3} - {\left (b^{2} d - d^{3}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (b x + a\right ) \sin \left (d x + c\right )}{b^{4} - 10 \, b^{2} d^{2} + 9 \, d^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^3*sin(b*x+a),x, algorithm="fricas")

[Out]

(6*b*d^2*cos(b*x + a)*cos(d*x + c) - (b^3 - b*d^2)*cos(b*x + a)*cos(d*x + c)^3 + 3*(2*d^3 - (b^2*d - d^3)*cos(
d*x + c)^2)*sin(b*x + a)*sin(d*x + c))/(b^4 - 10*b^2*d^2 + 9*d^4)

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 921 vs. \(2 (78) = 156\).
time = 2.36, size = 921, normalized size = 10.12 \begin {gather*} \begin {cases} x \sin {\left (a \right )} \cos ^{3}{\left (c \right )} & \text {for}\: b = 0 \wedge d = 0 \\- \frac {3 x \sin {\left (a - 3 d x \right )} \sin ^{2}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{8} + \frac {x \sin {\left (a - 3 d x \right )} \cos ^{3}{\left (c + d x \right )}}{8} - \frac {x \sin ^{3}{\left (c + d x \right )} \cos {\left (a - 3 d x \right )}}{8} + \frac {3 x \sin {\left (c + d x \right )} \cos {\left (a - 3 d x \right )} \cos ^{2}{\left (c + d x \right )}}{8} - \frac {\sin {\left (a - 3 d x \right )} \sin ^{3}{\left (c + d x \right )}}{8 d} + \frac {\sin ^{2}{\left (c + d x \right )} \cos {\left (a - 3 d x \right )} \cos {\left (c + d x \right )}}{4 d} + \frac {7 \cos {\left (a - 3 d x \right )} \cos ^{3}{\left (c + d x \right )}}{24 d} & \text {for}\: b = - 3 d \\\frac {3 x \sin {\left (a - d x \right )} \sin ^{2}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{8} + \frac {3 x \sin {\left (a - d x \right )} \cos ^{3}{\left (c + d x \right )}}{8} + \frac {3 x \sin ^{3}{\left (c + d x \right )} \cos {\left (a - d x \right )}}{8} + \frac {3 x \sin {\left (c + d x \right )} \cos {\left (a - d x \right )} \cos ^{2}{\left (c + d x \right )}}{8} - \frac {3 \sin {\left (a - d x \right )} \sin ^{3}{\left (c + d x \right )}}{8 d} + \frac {3 \sin ^{2}{\left (c + d x \right )} \cos {\left (a - d x \right )} \cos {\left (c + d x \right )}}{4 d} + \frac {5 \cos {\left (a - d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} & \text {for}\: b = - d \\\frac {3 x \sin {\left (a + d x \right )} \sin ^{2}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{8} + \frac {3 x \sin {\left (a + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8} - \frac {3 x \sin ^{3}{\left (c + d x \right )} \cos {\left (a + d x \right )}}{8} - \frac {3 x \sin {\left (c + d x \right )} \cos {\left (a + d x \right )} \cos ^{2}{\left (c + d x \right )}}{8} - \frac {3 \sin {\left (a + d x \right )} \sin ^{3}{\left (c + d x \right )}}{8 d} - \frac {3 \sin ^{2}{\left (c + d x \right )} \cos {\left (a + d x \right )} \cos {\left (c + d x \right )}}{4 d} - \frac {5 \cos {\left (a + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} & \text {for}\: b = d \\- \frac {3 x \sin {\left (a + 3 d x \right )} \sin ^{2}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{8} + \frac {x \sin {\left (a + 3 d x \right )} \cos ^{3}{\left (c + d x \right )}}{8} + \frac {x \sin ^{3}{\left (c + d x \right )} \cos {\left (a + 3 d x \right )}}{8} - \frac {3 x \sin {\left (c + d x \right )} \cos {\left (a + 3 d x \right )} \cos ^{2}{\left (c + d x \right )}}{8} - \frac {\sin {\left (a + 3 d x \right )} \sin ^{3}{\left (c + d x \right )}}{8 d} - \frac {\sin ^{2}{\left (c + d x \right )} \cos {\left (a + 3 d x \right )} \cos {\left (c + d x \right )}}{4 d} - \frac {7 \cos {\left (a + 3 d x \right )} \cos ^{3}{\left (c + d x \right )}}{24 d} & \text {for}\: b = 3 d \\- \frac {b^{3} \cos {\left (a + b x \right )} \cos ^{3}{\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} - \frac {3 b^{2} d \sin {\left (a + b x \right )} \sin {\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} + \frac {6 b d^{2} \sin ^{2}{\left (c + d x \right )} \cos {\left (a + b x \right )} \cos {\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} + \frac {7 b d^{2} \cos {\left (a + b x \right )} \cos ^{3}{\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} + \frac {6 d^{3} \sin {\left (a + b x \right )} \sin ^{3}{\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} + \frac {9 d^{3} \sin {\left (a + b x \right )} \sin {\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{b^{4} - 10 b^{2} d^{2} + 9 d^{4}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**3*sin(b*x+a),x)

[Out]

Piecewise((x*sin(a)*cos(c)**3, Eq(b, 0) & Eq(d, 0)), (-3*x*sin(a - 3*d*x)*sin(c + d*x)**2*cos(c + d*x)/8 + x*s
in(a - 3*d*x)*cos(c + d*x)**3/8 - x*sin(c + d*x)**3*cos(a - 3*d*x)/8 + 3*x*sin(c + d*x)*cos(a - 3*d*x)*cos(c +
d*x)**2/8 - sin(a - 3*d*x)*sin(c + d*x)**3/(8*d) + sin(c + d*x)**2*cos(a - 3*d*x)*cos(c + d*x)/(4*d) + 7*cos(
a - 3*d*x)*cos(c + d*x)**3/(24*d), Eq(b, -3*d)), (3*x*sin(a - d*x)*sin(c + d*x)**2*cos(c + d*x)/8 + 3*x*sin(a
- d*x)*cos(c + d*x)**3/8 + 3*x*sin(c + d*x)**3*cos(a - d*x)/8 + 3*x*sin(c + d*x)*cos(a - d*x)*cos(c + d*x)**2/
8 - 3*sin(a - d*x)*sin(c + d*x)**3/(8*d) + 3*sin(c + d*x)**2*cos(a - d*x)*cos(c + d*x)/(4*d) + 5*cos(a - d*x)*
cos(c + d*x)**3/(8*d), Eq(b, -d)), (3*x*sin(a + d*x)*sin(c + d*x)**2*cos(c + d*x)/8 + 3*x*sin(a + d*x)*cos(c +
d*x)**3/8 - 3*x*sin(c + d*x)**3*cos(a + d*x)/8 - 3*x*sin(c + d*x)*cos(a + d*x)*cos(c + d*x)**2/8 - 3*sin(a +
d*x)*sin(c + d*x)**3/(8*d) - 3*sin(c + d*x)**2*cos(a + d*x)*cos(c + d*x)/(4*d) - 5*cos(a + d*x)*cos(c + d*x)**
3/(8*d), Eq(b, d)), (-3*x*sin(a + 3*d*x)*sin(c + d*x)**2*cos(c + d*x)/8 + x*sin(a + 3*d*x)*cos(c + d*x)**3/8 +
x*sin(c + d*x)**3*cos(a + 3*d*x)/8 - 3*x*sin(c + d*x)*cos(a + 3*d*x)*cos(c + d*x)**2/8 - sin(a + 3*d*x)*sin(c
+ d*x)**3/(8*d) - sin(c + d*x)**2*cos(a + 3*d*x)*cos(c + d*x)/(4*d) - 7*cos(a + 3*d*x)*cos(c + d*x)**3/(24*d)
, Eq(b, 3*d)), (-b**3*cos(a + b*x)*cos(c + d*x)**3/(b**4 - 10*b**2*d**2 + 9*d**4) - 3*b**2*d*sin(a + b*x)*sin(
c + d*x)*cos(c + d*x)**2/(b**4 - 10*b**2*d**2 + 9*d**4) + 6*b*d**2*sin(c + d*x)**2*cos(a + b*x)*cos(c + d*x)/(
b**4 - 10*b**2*d**2 + 9*d**4) + 7*b*d**2*cos(a + b*x)*cos(c + d*x)**3/(b**4 - 10*b**2*d**2 + 9*d**4) + 6*d**3*
sin(a + b*x)*sin(c + d*x)**3/(b**4 - 10*b**2*d**2 + 9*d**4) + 9*d**3*sin(a + b*x)*sin(c + d*x)*cos(c + d*x)**2
/(b**4 - 10*b**2*d**2 + 9*d**4), True))

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Giac [A]
time = 0.39, size = 84, normalized size = 0.92 \begin {gather*} -\frac {\cos \left (b x + 3 \, d x + a + 3 \, c\right )}{8 \, {\left (b + 3 \, d\right )}} - \frac {3 \, \cos \left (b x + d x + a + c\right )}{8 \, {\left (b + d\right )}} - \frac {3 \, \cos \left (b x - d x + a - c\right )}{8 \, {\left (b - d\right )}} - \frac {\cos \left (b x - 3 \, d x + a - 3 \, c\right )}{8 \, {\left (b - 3 \, d\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^3*sin(b*x+a),x, algorithm="giac")

[Out]

-1/8*cos(b*x + 3*d*x + a + 3*c)/(b + 3*d) - 3/8*cos(b*x + d*x + a + c)/(b + d) - 3/8*cos(b*x - d*x + a - c)/(b
- d) - 1/8*cos(b*x - 3*d*x + a - 3*c)/(b - 3*d)

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Mupad [B]
time = 1.61, size = 297, normalized size = 3.26 \begin {gather*} -{\mathrm {e}}^{a\,1{}\mathrm {i}-c\,3{}\mathrm {i}+b\,x\,1{}\mathrm {i}-d\,x\,3{}\mathrm {i}}\,\left (\frac {b+3\,d}{16\,b^2-144\,d^2}+\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (b-3\,d\right )}{16\,b^2-144\,d^2}\right )-{\mathrm {e}}^{a\,1{}\mathrm {i}+c\,3{}\mathrm {i}+b\,x\,1{}\mathrm {i}+d\,x\,3{}\mathrm {i}}\,\left (\frac {b-3\,d}{16\,b^2-144\,d^2}+\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (b+3\,d\right )}{16\,b^2-144\,d^2}\right )-{\mathrm {e}}^{a\,1{}\mathrm {i}-c\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\left (\frac {3\,b+3\,d}{16\,b^2-16\,d^2}+\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (3\,b-3\,d\right )}{16\,b^2-16\,d^2}\right )-{\mathrm {e}}^{a\,1{}\mathrm {i}+c\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}+d\,x\,1{}\mathrm {i}}\,\left (\frac {3\,b-3\,d}{16\,b^2-16\,d^2}+\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (3\,b+3\,d\right )}{16\,b^2-16\,d^2}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^3*sin(a + b*x),x)

[Out]

- exp(a*1i - c*3i + b*x*1i - d*x*3i)*((b + 3*d)/(16*b^2 - 144*d^2) + (exp(- a*2i - b*x*2i)*(b - 3*d))/(16*b^2
- 144*d^2)) - exp(a*1i + c*3i + b*x*1i + d*x*3i)*((b - 3*d)/(16*b^2 - 144*d^2) + (exp(- a*2i - b*x*2i)*(b + 3*
d))/(16*b^2 - 144*d^2)) - exp(a*1i - c*1i + b*x*1i - d*x*1i)*((3*b + 3*d)/(16*b^2 - 16*d^2) + (exp(- a*2i - b*
x*2i)*(3*b - 3*d))/(16*b^2 - 16*d^2)) - exp(a*1i + c*1i + b*x*1i + d*x*1i)*((3*b - 3*d)/(16*b^2 - 16*d^2) + (e
xp(- a*2i - b*x*2i)*(3*b + 3*d))/(16*b^2 - 16*d^2))

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